What is the general solution for sin(2θ)=(sqrt(3))/2 ?

The general solution for sin(2θ)=(sqrt(3))/2 is θ= pi/6+pin,θ= pi/3+pin

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sin(2θ)=(sqrt(3))/2

sin (2 θ) = \frac{3}{2}

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

Solution steps

sin (2 θ) = \frac{3}{2}

General solutions for

sin (2 θ) = \frac{3}{2}

2 θ = \frac{π}{3} + 2 πn, 2 θ = \frac{2 π}{3} + 2 πn

Solve

2 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{6} + πn

Solve

2 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{3} + πn

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

arctan (\frac{π}{4})

sec (\frac{π}{4})

sec (\frac{2 π}{3})

cot (x) = 3

4 sin (x) - 3 cos (x) = 5

What is the general solution for sin(2θ)=(sqrt(3))/2 ?
The general solution for sin(2θ)=(sqrt(3))/2 is θ= pi/6+pin,θ= pi/3+pin