Is csc^2(x)tan^2(x)= 1/(cos^2(x)) ?

The answer to whether csc^2(x)tan^2(x)= 1/(cos^2(x)) is True

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prove csc^2(x)tan^2(x)= 1/(cos^2(x))

prove

csc^{2} (x) tan^{2} (x) = \frac{1}{cos ^{2} ( x )}

True

Solution steps

csc^{2} (x) tan^{2} (x) = \frac{1}{cos ^{2} ( x )}

Manipulating left side

csc^{2} (x) tan^{2} (x)

Express with sin, cos

= \frac{1}{cos ^{2} ( x )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{tan ( x )}{sin ( x ) cos ( x )} = tan^{2} (x) + 1

cos (θ) = 2 cos^{2} (\frac{θ}{2}) - 1

1 - sin^{2} (u) = cos^{2} (u)

cos (4 x) = 1 - 8 cos^{2} (x) + 8 cos^{4} (x)

cot (x) + tan (x) = \frac{1}{sin ( x ) cos ( x )}

Is csc^2(x)tan^2(x)= 1/(cos^2(x)) ?
The answer to whether csc^2(x)tan^2(x)= 1/(cos^2(x)) is True