Is cot^2(θ)=(cos^2(θ))/(sin^2(θ)) ?

The answer to whether cot^2(θ)=(cos^2(θ))/(sin^2(θ)) is True

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prove cot^2(θ)=(cos^2(θ))/(sin^2(θ))

prove

cot^{2} (θ) = \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

True

Solution steps

cot^{2} (θ) = \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

Manipulating left side

cot^{2} (θ)

Express with sin, cos

= \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

cos (π) = cos (- π)

2 (1 + sin^{2} (x)) = cos (2 x) + 1

sec^{2} (θ) - 1 = \frac{tan ( θ )}{cot ( θ )}

cot (x) = \frac{sin ( 2 x )}{1 - cos ( x ^{2} )}

cos (2 x) = cos (x) cos (x) - sin (x) sin (x)

Is cot^2(θ)=(cos^2(θ))/(sin^2(θ)) ?
The answer to whether cot^2(θ)=(cos^2(θ))/(sin^2(θ)) is True