Is (8/6)^2+1=(10/6)^2 ?

The answer to whether (8/6)^2+1=(10/6)^2 is True

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prove (8/6)^2+1=(10/6)^2

prove

(\frac{8}{6})^{2} + 1 = (\frac{10}{6})^{2}

True

Solution steps

(\frac{8}{6})^{2} + 1 = (\frac{10}{6})^{2}

Manipulating left side

(\frac{8}{6})^{2} + 1

Simplify

(\frac{8}{6})^{2} + 1 : \frac{25}{9}

= \frac{25}{9}

Manipulating right side

(\frac{10}{6})^{2}

Simplify

(\frac{10}{6})^{2} : \frac{25}{9}

= \frac{25}{9}

We showed that the two sides could take the same form

\Rightarrow True

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tan^{2} (x) (1 + cot^{2} (x)) = sec^{2} (x)

\frac{1 - sin ( x )}{cos ( x )} = 1 - tan (x)

1 - cos^{2} (x) - cos^{2} (x) = 1 - 2 cos^{2} (x)

\frac{( 1 + cot ^{2} ( x ) )}{sec ^{2} ( x )} = cot^{2} (x)