Is 1/(tan^2(θ))-cos(θ)=cos^2(θ) ?

The answer to whether 1/(tan^2(θ))-cos(θ)=cos^2(θ) is False

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prove 1/(tan^2(θ))-cos(θ)=cos^2(θ)

prove

\frac{1}{tan ^{2} ( θ )} - cos (θ) = cos^{2} (θ)

False

Solution steps

\frac{1}{tan ^{2} ( θ )} - cos (θ) = cos^{2} (θ)

Show that the two sides are not equal

\Rightarrow False

2 sin (x) = tan (x)

1 \cdot sin (t) + (- 1) \cdot cos (t - \frac{π}{2}) = 0

\frac{cot ( x )}{sec ( x ) - tan ( x )} = csc (x) + 1

csc (x) - cot (x) = \frac{1}{( csc ( x ) + cot ( x ) )}

\frac{csc ( x )}{cot ( x )} = \frac{1}{cos ( x )}

Is 1/(tan^2(θ))-cos(θ)=cos^2(θ) ?
The answer to whether 1/(tan^2(θ))-cos(θ)=cos^2(θ) is False