Is sin^2(β)+tan^2(β)+1= 2/(cos^2(β)) ?

The answer to whether sin^2(β)+tan^2(β)+1= 2/(cos^2(β)) is False

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prove sin^2(β)+tan^2(β)+1= 2/(cos^2(β))

prove

sin^{2} (β) + tan^{2} (β) + 1 = \frac{2}{cos ^{2} ( β )}

False

Solution steps

sin^{2} (β) + tan^{2} (β) + 1 = \frac{2}{cos ^{2} ( β )}

Show that the two sides are not equal

\Rightarrow False

cot (x) - 1 = csc (x) (cos (x) - sin (x))

sec (A) csc (A) = 1

sin^{2} (\frac{x}{2}) - cos^{2} (\frac{x}{2}) = - cos (x)

\frac{tan ^{2} ( x )}{1 + sec ( x )} = sec (x) - 1

csc (x) = sin (x)

Is sin^2(β)+tan^2(β)+1= 2/(cos^2(β)) ?
The answer to whether sin^2(β)+tan^2(β)+1= 2/(cos^2(β)) is False