Is (cos(x)*sec(x))/(tan(x))=cot(x) ?

The answer to whether (cos(x)*sec(x))/(tan(x))=cot(x) is True

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prove (cos(x)*sec(x))/(tan(x))=cot(x)

prove

\frac{cos ( x ) \cdot sec ( x )}{tan ( x )} = cot (x)

True

Solution steps

\frac{cos ( x ) sec ( x )}{tan ( x )} = cot (x)

Manipulating left side

\frac{cos ( x ) sec ( x )}{tan ( x )}

Express with sin, cos

= \frac{cos ( x )}{sin ( x )}

Use the basic trigonometric identity:

\frac{cos ( x )}{sin ( x )} = cot (x)

= cot (x)

We showed that the two sides could take the same form

\Rightarrow True

81 - 9 (3 sin (x))^{2} = 12 sec (x)

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} = cot^{2} (x)

\frac{1 - cos ( 2 x )}{cos ^{2} ( x )} = 2 tan^{2} (x)

sin^{2} (θ) = (sin (θ)) (sin (θ))

\frac{cos ^{2} ( θ )}{sin ( θ )} + sin (θ) = csc (θ)

Is (cos(x)*sec(x))/(tan(x))=cot(x) ?
The answer to whether (cos(x)*sec(x))/(tan(x))=cot(x) is True