Is sin^4(x)=sec^2(x)tan^2(x)+sec^2(x) ?

The answer to whether sin^4(x)=sec^2(x)tan^2(x)+sec^2(x) is False

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prove sin^4(x)=sec^2(x)tan^2(x)+sec^2(x)

prove

sin^{4} (x) = sec^{2} (x) tan^{2} (x) + sec^{2} (x)

False

Solution steps

sin^{4} (x) = sec^{2} (x) tan^{2} (x) + sec^{2} (x)

Show that the two sides are not equal

\Rightarrow False

(1 + cos (x)) (1 - sec (x)) = - 1

cot^{2} (\frac{v}{2}) = \frac{( sec ( v ) + 1 )}{( sec ( v ) - 1 )}

csc (θ) (1 - cos (θ)) (1 + cos (θ)) = sin (θ)

sec (θ) - \frac{1}{sec ( θ )} = sin (θ) tan (θ)

csc^{2} (θ) + sec^{2} (θ) = csc^{2} (θ) sec^{2} (θ)

Is sin^4(x)=sec^2(x)tan^2(x)+sec^2(x) ?
The answer to whether sin^4(x)=sec^2(x)tan^2(x)+sec^2(x) is False