Is (sin(θ)+cos(θ))/(sin(θ))=1+cot(θ) ?

The answer to whether (sin(θ)+cos(θ))/(sin(θ))=1+cot(θ) is True

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prove (sin(θ)+cos(θ))/(sin(θ))=1+cot(θ)

prove

\frac{sin ( θ ) + cos ( θ )}{sin ( θ )} = 1 + cot (θ)

True

Solution steps

\frac{sin ( θ ) + cos ( θ )}{sin ( θ )} = 1 + cot (θ)

Manipulating right side

1 + cot (θ)

Express with sin, cos

= \frac{cos ( θ ) + sin ( θ )}{sin ( θ )}

= \frac{sin ( θ ) + cos ( θ )}{sin ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

cos^{2} (x) (sec (x) + 1)^{2} = (cos (x) + 1)^{2}

sin^{2} (x) + cos (x^{2}) = 1

\frac{cos ( u )}{1 + tan ( u )} - \frac{sin ( u )}{1 + cot ( u )} = cos (u) - sin (u)

(sin (x) + cos (x))^{2} = 1 + 2 sin (x)

csc (θ) = \frac{1}{sec ( θ )}

Is (sin(θ)+cos(θ))/(sin(θ))=1+cot(θ) ?
The answer to whether (sin(θ)+cos(θ))/(sin(θ))=1+cot(θ) is True