Is (1-cos(2x))/(sin(x))=2sin(x) ?

The answer to whether (1-cos(2x))/(sin(x))=2sin(x) is True

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prove (1-cos(2x))/(sin(x))=2sin(x)

prove

\frac{1 - cos ( 2 x )}{sin ( x )} = 2 sin (x)

True

Solution steps

\frac{1 - cos ( 2 x )}{sin ( x )} = 2 sin (x)

Manipulating left side

\frac{1 - cos ( 2 x )}{sin ( x )}

Rewrite using trig identities

\frac{1 - cos ( 2 x )}{sin ( x )}

Use the Double Angle identity:

cos (2 x) = 1 - 2 sin^{2} (x)

= \frac{1 - ( 1 - 2 sin ^{2} ( x ) )}{sin ( x )}

Simplify

\frac{1 - ( 1 - 2 sin ^{2} ( x ) )}{sin ( x )} : 2 sin (x)

\frac{1 - ( 1 - 2 sin ^{2} ( x ) )}{sin ( x )}

Expand

1 - (1 - 2 sin^{2} (x)) : 2 sin^{2} (x)

1 - (1 - 2 sin^{2} (x))

- (1 - 2 sin^{2} (x)) : - 1 + 2 sin^{2} (x)

- (1 - 2 sin^{2} (x))

Distribute parentheses

= - (1) - (- 2 sin^{2} (x))

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - 1 + 2 sin^{2} (x)

= 1 - 1 + 2 sin^{2} (x)

1 - 1 = 0

= 2 sin^{2} (x)

= \frac{2 sin ^{2} ( x )}{sin ( x )}

Cancel the common factor:

sin (x)

= 2 sin (x)

= 2 sin (x)

= 2 sin (x)

We showed that the two sides could take the same form

\Rightarrow True

tan (θ) = sin (θ) sec (θ)

sin^{2} (x) = 1 - cos (2 x)

1 - (\frac{cos ^{2} ( x )}{1 + sin ( x )}) = sin (x)

sin (4 a) = 2 sin (2 a) cos (2 a)

tan (x) = sec (x) sin (x)

Is (1-cos(2x))/(sin(x))=2sin(x) ?
The answer to whether (1-cos(2x))/(sin(x))=2sin(x) is True