Is sec^2(x)=(sec(x))/(cos(x)) ?

The answer to whether sec^2(x)=(sec(x))/(cos(x)) is True

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prove sec^2(x)=(sec(x))/(cos(x))

prove

sec^{2} (x) = \frac{sec ( x )}{cos ( x )}

True

Solution steps

sec^{2} (x) = \frac{sec ( x )}{cos ( x )}

Manipulating right side

\frac{sec ( x )}{cos ( x )}

Express with sin, cos

\frac{sec ( x )}{cos ( x )}

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{\frac{1}{c o s ( x )}}{cos ( x )}

Simplify

\frac{\frac{1}{c o s ( x )}}{cos ( x )} : \frac{1}{cos ^{2} ( x )}

\frac{\frac{1}{c o s ( x )}}{cos ( x )}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{1}{cos ( x ) cos ( x )}

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

Add the numbers:

1 + 1 = 2

= cos^{2} (x)

= \frac{1}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )}

Rewrite using trig identities

Use the basic trigonometric identity:

cos (x) = \frac{1}{sec ( x )}

\frac{1}{( \frac{1}{s e c ( x )} ) ^{2}}

Simplify

\frac{1}{( \frac{1}{s e c ( x )} ) ^{2}}

(\frac{1}{sec ( x )})^{2} = \frac{1}{sec ^{2} ( x )}

(\frac{1}{sec ( x )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{sec ^{2} ( x )}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{sec ^{2} ( x )}

= \frac{1}{\frac{1}{s e c ^{2} ( x )}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{sec ^{2} ( x )}{1}

Apply rule

\frac{a}{1} = a

= sec^{2} (x)

sec^{2} (x)

sec^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

cot (θ) \cdot sin (θ) = cos (θ)

2 sin^{2} (θ) + sin (θ) - 1 = 0

\frac{1}{csc ( t ) - cot ( t )} = csc (t) + cot (t)

sin (\frac{5 π}{2} + x) = cos (x)

\frac{2}{cos ^{2} ( x ) - tan ^{2} ( x )} = 2 + tan^{2} (x)

Is sec^2(x)=(sec(x))/(cos(x)) ?
The answer to whether sec^2(x)=(sec(x))/(cos(x)) is True