Is (csc(x)+tan(x))cos(x)=sin(x)cot(x) ?

The answer to whether (csc(x)+tan(x))cos(x)=sin(x)cot(x) is False

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prove (csc(x)+tan(x))cos(x)=sin(x)cot(x)

prove

(csc (x) + tan (x)) cos (x) = sin (x) cot (x)

False

Solution steps

(csc (x) + tan (x)) cos (x) = sin (x) cot (x)

Show that the two sides are not equal

For

(csc (x) + tan (x)) cos (x) = sin (x) cot (x)

plug in

x = 1

(csc (1) + tan (1)) cos (1) = 1.48356 \dots

(csc (1) + tan (1)) cos (1)

Refine to a decimal form

= 1.48356 \dots

sin (1) cot (1) = 0.54030 \dots

sin (1) cot (1)

Refine to a decimal form

= 0.54030 \dots

The two sides are not equal

\Rightarrow False

3 tan^{2} (x) + 13 tan (x) = 4

csc (\frac{π}{2} - θ) = sec (θ)

sin (x) cos (x) = cot (x)

\frac{sin ( a + 2 a ) + 4 sin ^{3} ( a )}{3} = sin (a)

- sin^{2} (x) = - \frac{( 1 - cos ( 2 x ) )}{2}

Is (csc(x)+tan(x))cos(x)=sin(x)cot(x) ?
The answer to whether (csc(x)+tan(x))cos(x)=sin(x)cot(x) is False