Is prove-2tan^2(0)=2tan(0) ?

The answer to whether prove-2tan^2(0)=2tan(0) is True

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prove-2tan^2(0)=2tan(0)

prove

- 2 tan^{2} (0) = 2 tan (0)

True

Solution steps

- 2 tan^{2} (0) = 2 tan (0)

Manipulating left side

- 2 tan^{2} (0)

Simplify

- 2 tan^{2} (0) : 0

- 2 tan^{2} (0)

tan^{2} (0) = 0

tan^{2} (0)

Simplify

tan (0) : 0

tan (0)

Use the following trivial identity:

tan (0) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

= 0^{2}

Apply rule

0^{a} = 0

= 0

= - 2 \cdot 0

Apply rule

0 \cdot a = 0

= 0

= 0

Manipulating right side

2 tan (0)

Simplify

2 tan (0) : 0

2 tan (0)

Simplify

tan (0) : 0

tan (0)

Use the following trivial identity:

tan (0) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

= 2 \cdot 0

Apply rule

0 \cdot a = 0

= 0

= 0

We showed that the two sides could take the same form

\Rightarrow True

2 cot (x) sin (x) = 2 cos (x)

csc^{2} (x) (sin^{2} (x) - 1) = - cot^{2} (x)

cos (3 x) = cos (x) (4 cos^{2} (x) - 3)

\frac{1}{sin ( x ) cot ( x )} = sec (x)

csc (θ) + sin (θ) = \frac{2 - cos ^{2} ( θ )}{sin ( θ )}

Is prove-2tan^2(0)=2tan(0) ?
The answer to whether prove-2tan^2(0)=2tan(0) is True