Is tan^2(x)-sin^2(x)=tan^2(x) ?

The answer to whether tan^2(x)-sin^2(x)=tan^2(x) is False

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prove tan^2(x)-sin^2(x)=tan^2(x)

prove

tan^{2} (x) - sin^{2} (x) = tan^{2} (x)

False

Solution steps

tan^{2} (x) - sin^{2} (x) = tan^{2} (x)

Show that the two sides are not equal

For

tan^{2} (x) - sin^{2} (x) = tan^{2} (x)

plug in

x = 1

tan^{2} (1) - sin^{2} (1) = 1.71744 \dots

tan^{2} (1) - sin^{2} (1)

Refine to a decimal form

= 1.71744 \dots

tan^{2} (1) = 2.42551 \dots

tan^{2} (1)

Refine to a decimal form

= 2.42551 \dots

The two sides are not equal

\Rightarrow False

sin (x) ((1 + cot^{2} (x))) = csc (x)

\frac{1}{tan ^{2} ( x )} = \frac{cos ^{2} ( x )}{sin ^{2} ( x )}

cot^{2} (x) + csc^{2} (x) = 2 csc^{2} (x)

sin^{2} (x) - \frac{sin ^{2} ( x )}{cos ^{2} ( x )} = 1

sin (3 θ) + sin (θ) = 2 sin (2 θ) cos (θ)

Is tan^2(x)-sin^2(x)=tan^2(x) ?
The answer to whether tan^2(x)-sin^2(x)=tan^2(x) is False