Is (sin(x)+tan(x))/(1+sec(x))=tan(x) ?

The answer to whether (sin(x)+tan(x))/(1+sec(x))=tan(x) is False

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prove (sin(x)+tan(x))/(1+sec(x))=tan(x)

prove

\frac{sin ( x ) + tan ( x )}{1 + sec ( x )} = tan (x)

False

Solution steps

\frac{sin ( x ) + tan ( x )}{1 + sec ( x )} = tan (x)

Show that the two sides are not equal

For

\frac{sin ( x ) + tan ( x )}{1 + sec ( x )} = tan (x)

plug in

x = 1

\frac{sin ( 1 ) + tan ( 1 )}{1 + sec ( 1 )} = 0.84147 \dots

\frac{sin ( 1 ) + tan ( 1 )}{1 + sec ( 1 )}

Refine to a decimal form

= 0.84147 \dots

tan (1) = 1.55740 \dots

tan (1)

Refine to a decimal form

= 1.55740 \dots

The two sides are not equal

\Rightarrow False

sec (A) - cos (A) = tan (A) sin (A)

cos^{2} (z) + sin^{2} (z) = 1

cot (u) - csc (u) = \frac{sin ( u )}{1 + cos ( u )}

cos (θ) tan (- θ) = - sin (θ)

tan^{3} (x) cot (x) = sec^{2} (x) - 1

Is (sin(x)+tan(x))/(1+sec(x))=tan(x) ?
The answer to whether (sin(x)+tan(x))/(1+sec(x))=tan(x) is False