Is (cot(x))/(tan(x)sec(x))=csc(x)-1 ?

The answer to whether (cot(x))/(tan(x)sec(x))=csc(x)-1 is False

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prove (cot(x))/(tan(x)sec(x))=csc(x)-1

prove

\frac{cot ( x )}{tan ( x ) sec ( x )} = csc (x) - 1

False

Solution steps

\frac{cot ( x )}{tan ( x ) sec ( x )} = csc (x) - 1

Show that the two sides are not equal

For

\frac{cot ( x )}{tan ( x ) sec ( x )} = csc (x) - 1

plug in

x = 1

\frac{cot ( 1 )}{tan ( 1 ) sec ( 1 )} = 0.22275 \dots

\frac{cot ( 1 )}{tan ( 1 ) sec ( 1 )}

Refine to a decimal form

= 0.22275 \dots

csc (1) - 1 = 0.18839 \dots

csc (1) - 1

Refine to a decimal form

= 0.18839 \dots

The two sides are not equal

\Rightarrow False

cos (\frac{x}{2}) = \frac{( 1 + cos ( x ) )}{2}

sin^{2} (x) - \frac{cos ( x ) sin ( x )}{tan ( x )} = 1

tan^{2} (A) + 1 = sec^{2} (A)

\frac{tan ( x ) + 1}{sec ( x )} = sin (x) + cos (x)

cos (\frac{π}{2} - x) cot (x) = cos (x)

Is (cot(x))/(tan(x)sec(x))=csc(x)-1 ?
The answer to whether (cot(x))/(tan(x)sec(x))=csc(x)-1 is False