Is tan(5x)=tan(3x)sec(2x)-tan(3x) ?

The answer to whether tan(5x)=tan(3x)sec(2x)-tan(3x) is False

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prove tan(5x)=tan(3x)sec(2x)-tan(3x)

prove

tan (5 x) = tan (3 x) sec (2 x) - tan (3 x)

False

Solution steps

tan (5 x) = tan (3 x) sec (2 x) - tan (3 x)

Show that the two sides are not equal

For

tan (5 x) = tan (3 x) sec (2 x) - tan (3 x)

plug in

x = 1

tan (5 \cdot 1) = - 3.38051 \dots

tan (5 \cdot 1)

Refine to a decimal form

= - 3.38051 \dots

tan (3 \cdot 1) sec (2 \cdot 1) - tan (3 \cdot 1) = 0.48508 \dots

tan (3 \cdot 1) sec (2 \cdot 1) - tan (3 \cdot 1)

Refine to a decimal form

= 0.48508 \dots

The two sides are not equal

\Rightarrow False

1 - 2 cos^{2} (x) = sin^{2} (x) - cos^{2} (x)

sin (4 0^{\circ}) = 2 \cdot sin (2 0^{\circ}) \cdot cos (2 0^{\circ})

9 sec (y) cos (y) = 9

- sin (- x) = sin (x)

tan^{2} (x) + 2 = sec^{2} (x) + 1

Is tan(5x)=tan(3x)sec(2x)-tan(3x) ?
The answer to whether tan(5x)=tan(3x)sec(2x)-tan(3x) is False