Is (cos(x)+tan(x))^2=csc^2(x)sec^2(x) ?

The answer to whether (cos(x)+tan(x))^2=csc^2(x)sec^2(x) is False

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prove (cos(x)+tan(x))^2=csc^2(x)sec^2(x)

prove

(cos (x) + tan (x))^{2} = csc^{2} (x) sec^{2} (x)

False

Solution steps

(cos (x) + tan (x))^{2} = csc^{2} (x) sec^{2} (x)

Show that the two sides are not equal

For

(cos (x) + tan (x))^{2} = csc^{2} (x) sec^{2} (x)

plug in

x = 1

(cos (1) + tan (1))^{2} = 4.40038 \dots

(cos (1) + tan (1))^{2}

Refine to a decimal form

= 4.40038 \dots

csc^{2} (1) sec^{2} (1) = 4.83780 \dots

csc^{2} (1) sec^{2} (1)

Refine to a decimal form

= 4.83780 \dots

The two sides are not equal

\Rightarrow False

tan (x) (2 - cos (x))^{2} = 0

sin (A) = csc (A) tan (A)

sec (A) csc (A) = sec (A) cot (A)

1 - 2 sin^{2} (x) = - 1 + 2 cos^{2} (x)

\frac{1}{cos ( x )} - sin (x) tan (x) = cos (x)

Is (cos(x)+tan(x))^2=csc^2(x)sec^2(x) ?
The answer to whether (cos(x)+tan(x))^2=csc^2(x)sec^2(x) is False