Is (sin(x)+cos(x))/(sin(x))=1+cot(x) ?

The answer to whether (sin(x)+cos(x))/(sin(x))=1+cot(x) is True

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prove (sin(x)+cos(x))/(sin(x))=1+cot(x)

prove

\frac{sin ( x ) + cos ( x )}{sin ( x )} = 1 + cot (x)

True

Solution steps

\frac{sin ( x ) + cos ( x )}{sin ( x )} = 1 + cot (x)

Manipulating right side

1 + cot (x)

Express with sin, cos

1 + cot (x)

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= 1 + \frac{cos ( x )}{sin ( x )}

Simplify

1 + \frac{cos ( x )}{sin ( x )} : \frac{sin ( x ) + cos ( x )}{sin ( x )}

1 + \frac{cos ( x )}{sin ( x )}

Convert element to fraction:

1 = \frac{1 sin ( x )}{sin ( x )}

= \frac{1 \cdot sin ( x )}{sin ( x )} + \frac{cos ( x )}{sin ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot sin ( x ) + cos ( x )}{sin ( x )}

Multiply:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x ) + cos ( x )}{sin ( x )}

= \frac{sin ( x ) + cos ( x )}{sin ( x )}

= \frac{cos ( x ) + sin ( x )}{sin ( x )}

= \frac{sin ( x ) + cos ( x )}{sin ( x )}

We showed that the two sides could take the same form

\Rightarrow True

sin^{2} (θ) + 2 cos^{2} (θ) - 1 = cos^{2} (θ)

\frac{1}{sin ( x ) cos ( x )} = 2 csc (2 x)

(cos (x) + sin (x))^{2} = 2 sin (x) cos (x) + 1

cos (θ) = - cos (- θ)

sin (θ) + cos (θ) = sin (θ + 4 5^{\circ})

Is (sin(x)+cos(x))/(sin(x))=1+cot(x) ?
The answer to whether (sin(x)+cos(x))/(sin(x))=1+cot(x) is True