Is (tan^2(t))/(sec(t))=sec(t)-cot(t) ?

The answer to whether (tan^2(t))/(sec(t))=sec(t)-cot(t) is False

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prove (tan^2(t))/(sec(t))=sec(t)-cot(t)

prove

\frac{tan ^{2} ( t )}{sec ( t )} = sec (t) - cot (t)

False

Solution steps

\frac{tan ^{2} ( t )}{sec ( t )} = sec (t) - cot (t)

Show that the two sides are not equal

For

\frac{tan ^{2} ( t )}{sec ( t )} = sec (t) - cot (t)

plug in

t = 1

\frac{tan ^{2} ( 1 )}{sec ( 1 )} = 1.31051 \dots

\frac{tan ^{2} ( 1 )}{sec ( 1 )}

Refine to a decimal form

= 1.31051 \dots

sec (1) - cot (1) = 1.20872 \dots

sec (1) - cot (1)

Refine to a decimal form

= 1.20872 \dots

The two sides are not equal

\Rightarrow False

81 - 9 (3 sin (x))^{2} = 9 cos (x)

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(1 + tan (a)) \cdot (1 - tan (a)) = 2 - sec^{2} (a)

(cot (x)) (sec (x)) (sin (x)) = 1

\frac{cos ^{2} ( x ) - 4}{cos ( x ) - 2} = cos (x) + 2

Is (tan^2(t))/(sec(t))=sec(t)-cot(t) ?
The answer to whether (tan^2(t))/(sec(t))=sec(t)-cot(t) is False