Popular >

prove 1/(csc^2(x))=1-cos^2(x)

الحلّ

prove

\frac{1}{csc ^{2} ( x )} = 1 - cos^{2} (x)

صحيح

خطوات الحلّ

\frac{1}{csc ^{2} ( x )} = 1 - cos^{2} (x)

قم بالعمل على الطرف الأيسر

\frac{1}{csc ^{2} ( x )}

sin, cos :

عبّر بواسطة

\frac{1}{csc ^{2} ( x )}

csc (x) = \frac{1}{sin ( x )}

:Use the basic trigonometric identity

= \frac{1}{( \frac{1}{s i n ( x )} ) ^{2}}

\frac{1}{( \frac{1}{s i n ( x )} ) ^{2}}

بسّط:

sin^{2} (x)

\frac{1}{( \frac{1}{s i n ( x )} ) ^{2}}

(\frac{1}{sin ( x )})^{2} = \frac{1}{sin ^{2} ( x )}

(\frac{1}{sin ( x )})^{2}

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

:فعّل قانون القوى

= \frac{1 ^{2}}{sin ^{2} ( x )}

1^{a} = 1

فعّل القانون

1^{2} = 1

= \frac{1}{sin ^{2} ( x )}

= \frac{1}{\frac{1}{s i n ^{2} ( x )}}

\frac{1}{\frac{b}{c}} = \frac{c}{b}

: استخدم ميزات الكسور التالية

= \frac{sin ^{2} ( x )}{1}

\frac{a}{1} = a

فعّل القانون

= sin^{2} (x)

= sin^{2} (x)

= sin^{2} (x)

Rewrite using trig identities

sin^{2} (x)

cos^{2} (x) + sin^{2} (x) = 1

:فعّل نطريّة فيتاغوروس

sin^{2} (x) = 1 - cos^{2} (x)

= 1 - cos^{2} (x)

= 1 - cos^{2} (x)

أظهرنا بأنّ الطرفين من الممكن أن تكون لهما نفس الصورة

\Rightarrow صحيح

tan^{2} (x) - (sec (x) + 1) (sec (x) - 1) = 0

csc (u) sin (u) - cos^{2} (u) = sin^{2} (u)

2 cos^{2} (u) - cos (2 u) = 1

sec^{4} (θ) = sec^{2} (θ) tan^{2} (θ) + sec^{2} (θ)

sin^{2} (θ) = 1 - \frac{1}{sec ^{2} ( θ )}