Is sin(x)+cos(x)sec^2(x)=sec^2(x) ?

The answer to whether sin(x)+cos(x)sec^2(x)=sec^2(x) is False

Popular >

prove sin(x)+cos(x)sec^2(x)=sec^2(x)

prove

sin (x) + cos (x) sec^{2} (x) = sec^{2} (x)

False

Solution steps

sin (x) + cos (x) sec^{2} (x) = sec^{2} (x)

Show that the two sides are not equal

For

sin (x) + cos (x) sec^{2} (x) = sec^{2} (x)

plug in

x = 1

sin (1) + cos (1) sec^{2} (1) = 2.69228 \dots

sin (1) + cos (1) sec^{2} (1)

Refine to a decimal form

= 2.69228 \dots

sec^{2} (1) = 3.42551 \dots

sec^{2} (1)

Refine to a decimal form

= 3.42551 \dots

The two sides are not equal

\Rightarrow False

\frac{1}{( sec ( y ) - tan ( y ) )} = sec (y) + tan (y)

tan (θ) (cos (θ) + cot (θ)) = sin (θ) + 1

2 cos (2 x) = 4 cos^{2} (x) - 2

tan (\frac{π}{4} - θ) = \frac{cos ( 2 θ )}{1 + sin ( 2 θ )}

\frac{1 - sin ( 2 x )}{cos ( 2 x )} = \frac{cos ( 2 x )}{1 + sin ( 2 x )}

Is sin(x)+cos(x)sec^2(x)=sec^2(x) ?
The answer to whether sin(x)+cos(x)sec^2(x)=sec^2(x) is False