Is sin(3a)+sin(a)=4sin(a)-4sin(3a) ?

The answer to whether sin(3a)+sin(a)=4sin(a)-4sin(3a) is False

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prove sin(3a)+sin(a)=4sin(a)-4sin(3a)

prove

sin (3 a) + sin (a) = 4 sin (a) - 4 sin (3 a)

False

Solution steps

sin (3 a) + sin (a) = 4 sin (a) - 4 sin (3 a)

Show that the two sides are not equal

For

sin (3 a) + sin (a) = 4 sin (a) - 4 sin (3 a)

plug in

a = 1

sin (3 \cdot 1) + sin (1) = 0.98259 \dots

sin (3 \cdot 1) + sin (1)

Refine to a decimal form

= 0.98259 \dots

4 sin (1) - 4 sin (3 \cdot 1) = 2.80140 \dots

4 sin (1) - 4 sin (3 \cdot 1)

Refine to a decimal form

= 2.80140 \dots

The two sides are not equal

\Rightarrow False

tan (β) = \frac{cos ( β )}{sin ( β ) cot ^{2} ( β )}

cos (2 θ) = cos^{(2)} (θ) - sin^{(2)} (θ)

2 sec (β) = 2 \cdot \frac{1}{cos ( β )}

\frac{sin ^{2} ( x )}{cos ( x )} = sin (x) tan (x)

csc^{2} (x) sec^{2} (x) = sec^{2} (x) + csc^{2} (x)

Is sin(3a)+sin(a)=4sin(a)-4sin(3a) ?
The answer to whether sin(3a)+sin(a)=4sin(a)-4sin(3a) is False