Is (tan(θ)+sec^2(θ)-sec(θ))/(sec(θ))=tan^2(θ)+sin(θ) ?

The answer to whether (tan(θ)+sec^2(θ)-sec(θ))/(sec(θ))=tan^2(θ)+sin(θ) is False

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prove (tan(θ)+sec^2(θ)-sec(θ))/(sec(θ))=tan^2(θ)+sin(θ)

prove

\frac{tan ( θ ) + sec ^{2} ( θ ) - sec ( θ )}{sec ( θ )} = tan^{2} (θ) + sin (θ)

False

Solution steps

\frac{tan ( θ ) + sec ^{2} ( θ ) - sec ( θ )}{sec ( θ )} = tan^{2} (θ) + sin (θ)

Show that the two sides are not equal

For

\frac{tan ( θ ) + sec ^{2} ( θ ) - sec ( θ )}{sec ( θ )} = tan^{2} (θ) + sin (θ)

plug in

θ = 1

\frac{tan ( 1 ) + sec ^{2} ( 1 ) - sec ( 1 )}{sec ( 1 )} = 1.69228 \dots

\frac{tan ( 1 ) + sec ^{2} ( 1 ) - sec ( 1 )}{sec ( 1 )}

Refine to a decimal form

= 1.69228 \dots

tan^{2} (1) + sin (1) = 3.26698 \dots

tan^{2} (1) + sin (1)

Refine to a decimal form

= 3.26698 \dots

The two sides are not equal

\Rightarrow False

sin (\frac{9 π}{4}) = sin (\frac{3}{4} π + 2 π)

\frac{cos ( 2 θ )}{sin ( 2 θ )} = 2 cos (2 θ)

\frac{1 - tan ^{2} ( A )}{1 + tan ^{2} ( A )} = cos (2 A)

tan (θ) = \frac{sin ( 2 θ )}{1 + cos ( 2 θ )}

\frac{cot ^{2} ( b ) - 1}{2 cot ( b )} = cot (2 b)

Is (tan(θ)+sec^2(θ)-sec(θ))/(sec(θ))=tan^2(θ)+sin(θ) ?
The answer to whether (tan(θ)+sec^2(θ)-sec(θ))/(sec(θ))=tan^2(θ)+sin(θ) is False