Is prove-8cos(2x)-(0)(2cos(2x))=-8cos(2x) ?

The answer to whether prove-8cos(2x)-(0)(2cos(2x))=-8cos(2x) is True

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prove-8cos(2x)-(0)(2cos(2x))=-8cos(2x)

prove

- 8 cos (2 x) - (0) (2 cos (2 x)) = - 8 cos (2 x)

True

Solution steps

- 8 cos (2 x) - 0 \cdot 2 cos (2 x) = - 8 cos (2 x)

Manipulating left side

- 8 cos (2 x) - 02 cos (2 x)

Simplify

= - 8 cos (2 x)

We showed that the two sides could take the same form

\Rightarrow True

sec^{2} (x) cot^{2} (x) = 1 + cot^{2} (x)

cos (2 B) = \frac{1 - tan ^{2} ( B )}{1 + tan ^{2} ( B )}

sec (u) cos (u) - cos^{2} (u) = sin^{2} (u)

\frac{1 + sec ( x )}{1 + cos ( x )} = sec (x)

\frac{1 - sin ^{2} ( x )}{sin ( x )} = cot (x) cos (x)

Is prove-8cos(2x)-(0)(2cos(2x))=-8cos(2x) ?
The answer to whether prove-8cos(2x)-(0)(2cos(2x))=-8cos(2x) is True