Is csc(θ)-sin(θ)=cot(θ)csc(θ) ?

The answer to whether csc(θ)-sin(θ)=cot(θ)csc(θ) is False

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prove csc(θ)-sin(θ)=cot(θ)csc(θ)

prove

csc (θ) - sin (θ) = cot (θ) csc (θ)

False

Solution steps

csc (θ) - sin (θ) = cot (θ) csc (θ)

Show that the two sides are not equal

For

csc (θ) - sin (θ) = cot (θ) csc (θ)

plug in

θ = 1

csc (1) - sin (1) = 0.34692 \dots

csc (1) - sin (1)

Refine to a decimal form

= 0.34692 \dots

cot (1) csc (1) = 0.76305 \dots

cot (1) csc (1)

Refine to a decimal form

= 0.76305 \dots

The two sides are not equal

\Rightarrow False

cos (8 θ) = cos^{2} (4 θ) - sin^{2} (4 θ)

2 sec (2 α) cos (2 α) = 2

\frac{1}{sec ( x )} + 1 = \frac{sec ( x ) + 1}{sec ( x )}

tan^{2} (θ) = sec (θ) csc (θ) tan (θ) - 1

sin (x + y) = cos (\frac{π}{2} - (x + y))

Is csc(θ)-sin(θ)=cot(θ)csc(θ) ?
The answer to whether csc(θ)-sin(θ)=cot(θ)csc(θ) is False