Is sec(x)+cos(x)=1+cos^2(x) ?

The answer to whether sec(x)+cos(x)=1+cos^2(x) is False

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prove sec(x)+cos(x)=1+cos^2(x)

prove

sec (x) + cos (x) = 1 + cos^{2} (x)

False

Solution steps

sec (x) + cos (x) = 1 + cos^{2} (x)

Show that the two sides are not equal

For

sec (x) + cos (x) = 1 + cos^{2} (x)

plug in

x = 1

sec (1) + cos (1) = 2.39111 \dots

sec (1) + cos (1)

Refine to a decimal form

= 2.39111 \dots

1 + cos^{2} (1) = 1.29192 \dots

1 + cos^{2} (1)

Refine to a decimal form

= 1.29192 \dots

The two sides are not equal

\Rightarrow False

(cot (x) + tan (x)) sin (x) = sec (x)

\frac{cos ^{2} ( x )}{1 - sin ( x )} = sin (x) + 1

csc (x) - cos (x) tan (x) = csc (x) - sin (x)

2 sec^{2} (x) = (1 + 2 tan (x))^{2}

sin^{6} (a) + cos^{6} (a) = 1 - 3 sin^{2} (a) \cdot cos^{2} (a)

Is sec(x)+cos(x)=1+cos^2(x) ?
The answer to whether sec(x)+cos(x)=1+cos^2(x) is False