Is 1+(tan(a))^2=1+tan^2(a) ?

The answer to whether 1+(tan(a))^2=1+tan^2(a) is True

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prove 1+(tan(a))^2=1+tan^2(a)

prove

1 + (tan (a))^{2} = 1 + tan^{2} (a)

True

Solution steps

1 + (tan (a))^{2} = 1 + tan^{2} (a)

The two sides are the same

\Rightarrow True

sec (\frac{x}{2}) = \frac{1}{cos ( \frac{x}{2} )}

1 - sin (x) = cot (x)

4 cos^{2} (θ) + 4 sin^{2} (θ) = 4

\frac{- cos ^{2} ( 2 θ )}{2} = \frac{- 1 - cos ( 4 θ )}{8}

\frac{1 - cos ( x )}{- 1 + sec ( x )} = cos (x)

Is 1+(tan(a))^2=1+tan^2(a) ?
The answer to whether 1+(tan(a))^2=1+tan^2(a) is True