Is (1+sec(θ))/(sec^2(θ))=1+cos^2(θ) ?

The answer to whether (1+sec(θ))/(sec^2(θ))=1+cos^2(θ) is False

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prove (1+sec(θ))/(sec^2(θ))=1+cos^2(θ)

prove

\frac{1 + sec ( θ )}{sec ^{2} ( θ )} = 1 + cos^{2} (θ)

False

Solution steps

\frac{1 + sec ( θ )}{sec ^{2} ( θ )} = 1 + cos^{2} (θ)

Show that the two sides are not equal

For

\frac{1 + sec ( θ )}{sec ^{2} ( θ )} = 1 + cos^{2} (θ)

plug in

θ = 1

\frac{1 + sec ( 1 )}{sec ^{2} ( 1 )} = 0.83222 \dots

\frac{1 + sec ( 1 )}{sec ^{2} ( 1 )}

Refine to a decimal form

= 0.83222 \dots

1 + cos^{2} (1) = 1.29192 \dots

1 + cos^{2} (1)

Refine to a decimal form

= 1.29192 \dots

The two sides are not equal

\Rightarrow False

\frac{1}{cos ( x ) + 1} + \frac{1}{tan ( x ) + 1} = 1

\frac{1}{csc ( x ) + 1} + \frac{1}{csc ( x ) - 1} = 2 sec (x) tan (x)

25 cos^{2} (x) = 25 - 25 sin^{2} (x)

\frac{1}{1 - sin ( θ )} + \frac{1}{1 + sin ( θ )} = 4 tan (θ)

sin (18 0^{\circ} - θ) = sin (θ)

Is (1+sec(θ))/(sec^2(θ))=1+cos^2(θ) ?
The answer to whether (1+sec(θ))/(sec^2(θ))=1+cos^2(θ) is False