Is 2cot^2(x)sin^2(x)=1+2cos(x) ?

The answer to whether 2cot^2(x)sin^2(x)=1+2cos(x) is False

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prove 2cot^2(x)sin^2(x)=1+2cos(x)

prove

2 cot^{2} (x) sin^{2} (x) = 1 + 2 cos (x)

False

Solution steps

2 cot^{2} (x) sin^{2} (x) = 1 + 2 cos (x)

Show that the two sides are not equal

For

2 cot^{2} (x) sin^{2} (x) = 1 + 2 cos (x)

plug in

x = 1

2 cot^{2} (1) sin^{2} (1) = 0.58385 \dots

2 cot^{2} (1) sin^{2} (1)

Refine to a decimal form

= 0.58385 \dots

1 + 2 cos (1) = 2.08060 \dots

1 + 2 cos (1)

Refine to a decimal form

= 2.08060 \dots

The two sides are not equal

\Rightarrow False

\frac{sin ( a )}{1 + cos ( a )} + cot (a) = csc (a)

(cos (x) + sin (x)) 2 = 1 + 2 sin (x) cos (x)

cos (x) = cos^{2} (\frac{x}{2}) - sin^{2} (\frac{x}{2})

sin (y) tan (y) = cos (y)

sec^{4} (\frac{x}{3}) = \frac{( sec ^{4} ( x ) )}{3}

Is 2cot^2(x)sin^2(x)=1+2cos(x) ?
The answer to whether 2cot^2(x)sin^2(x)=1+2cos(x) is False