Is 3-3(cos(x)-sin(x))^2=-3sin(2x) ?

The answer to whether 3-3(cos(x)-sin(x))^2=-3sin(2x) is False

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prove 3-3(cos(x)-sin(x))^2=-3sin(2x)

prove

3 - 3 (cos (x) - sin (x))^{2} = - 3 sin (2 x)

False

Solution steps

3 - 3 (cos (x) - sin (x))^{2} = - 3 sin (2 x)

Show that the two sides are not equal

For

3 - 3 (cos (x) - sin (x))^{2} = - 3 sin (2 x)

plug in

x = 1

3 - 3 (cos (1) - sin (1))^{2} = 2.72789 \dots

3 - 3 (cos (1) - sin (1))^{2}

Refine to a decimal form

= 2.72789 \dots

- 3 sin (2 \cdot 1) = - 2.72789 \dots

- 3 sin (2 \cdot 1)

Refine to a decimal form

= - 2.72789 \dots

The two sides are not equal

\Rightarrow False

\frac{cot ( T ) - tan ( T )}{sin ( T ) + cos ( T )} = csc (T) - sec (T)

csc (\frac{π}{2} - x) cos (x) = 1

1 - 2 cos^{2} (4) = 2 sin^{2} (4) - 1

\frac{tan ( θ )}{cot ( θ ) + tan ( θ )} = sin^{2} (θ)

2 sin (x) + (2 + 2) = - 2 csc (x)

Is 3-3(cos(x)-sin(x))^2=-3sin(2x) ?
The answer to whether 3-3(cos(x)-sin(x))^2=-3sin(2x) is False