Is (csc(x))/(1+tan(x))=cot^2(x) ?

The answer to whether (csc(x))/(1+tan(x))=cot^2(x) is False

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prove (csc(x))/(1+tan(x))=cot^2(x)

prove

\frac{csc ( x )}{1 + tan ( x )} = cot^{2} (x)

False

Solution steps

\frac{csc ( x )}{1 + tan ( x )} = cot^{2} (x)

Show that the two sides are not equal

For

\frac{csc ( x )}{1 + tan ( x )} = cot^{2} (x)

plug in

x = 1

\frac{csc ( 1 )}{1 + tan ( 1 )} = 0.46468 \dots

\frac{csc ( 1 )}{1 + tan ( 1 )}

Refine to a decimal form

= 0.46468 \dots

cot^{2} (1) = 0.41228 \dots

cot^{2} (1)

Refine to a decimal form

= 0.41228 \dots

The two sides are not equal

\Rightarrow False

sin^{2} (x) = tan^{2} (x) + 1

\frac{1}{cot ( x ) + 1} = \frac{tan ( x )}{tan ( x ) + 1}

\frac{csc ^{2} ( θ )}{csc ^{2} ( θ ) - 2} = sec (2 θ)

cos^{2} (u) = \frac{1}{2} + \frac{1}{2} cos (2 u)

2 sin (- y) cos (x) = 2 sin (- y) cos (x)

Is (csc(x))/(1+tan(x))=cot^2(x) ?
The answer to whether (csc(x))/(1+tan(x))=cot^2(x) is False