Is csc(x^2)sec(x^2)=csc(x^2)+sec(x^2) ?

The answer to whether csc(x^2)sec(x^2)=csc(x^2)+sec(x^2) is False

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prove csc(x^2)sec(x^2)=csc(x^2)+sec(x^2)

prove

csc (x^{2}) sec (x^{2}) = csc (x^{2}) + sec (x^{2})

False

Solution steps

csc (x^{2}) sec (x^{2}) = csc (x^{2}) + sec (x^{2})

Show that the two sides are not equal

For

csc (x^{2}) sec (x^{2}) = csc (x^{2}) + sec (x^{2})

plug in

x = 1

csc (1^{2}) sec (1^{2}) = 2.19950 \dots

csc (1^{2}) sec (1^{2})

Refine to a decimal form

= 2.19950 \dots

csc (1^{2}) + sec (1^{2}) = 3.03921 \dots

csc (1^{2}) + sec (1^{2})

Refine to a decimal form

= 3.03921 \dots

The two sides are not equal

\Rightarrow False

tan (\frac{θ}{2}) = csc^{2} (θ) - cot^{2} (θ)

4 + 4 cos (2 x) = 8 cos^{2} (x)

\frac{sec ( θ ) csc ( θ )}{2} = csc (2 θ)

\frac{cos ( x )}{cot ( x ) sin ( x )} = 1

\frac{1 + cos ( θ )}{csc ( θ )} = sin (θ) + cos (θ)

Is csc(x^2)sec(x^2)=csc(x^2)+sec(x^2) ?
The answer to whether csc(x^2)sec(x^2)=csc(x^2)+sec(x^2) is False