Is sec(x)-tan(x)=(cos^2(x))/(sin(x)) ?

The answer to whether sec(x)-tan(x)=(cos^2(x))/(sin(x)) is False

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prove sec(x)-tan(x)=(cos^2(x))/(sin(x))

prove

sec (x) - tan (x) = \frac{cos ^{2} ( x )}{sin ( x )}

False

Solution steps

sec (x) - tan (x) = \frac{cos ^{2} ( x )}{sin ( x )}

Show that the two sides are not equal

For

sec (x) - tan (x) = \frac{cos ^{2} ( x )}{sin ( x )}

plug in

x = 1

sec (1) - tan (1) = 0.29340 \dots

sec (1) - tan (1)

Refine to a decimal form

= 0.29340 \dots

\frac{cos ^{2} ( 1 )}{sin ( 1 )} = 0.34692 \dots

\frac{cos ^{2} ( 1 )}{sin ( 1 )}

Refine to a decimal form

= 0.34692 \dots

The two sides are not equal

\Rightarrow False

3 - 6 sin^{2} (x) = - 3 cos (2 x)

(sin (\frac{5 \cdot \frac{π}{3}}{4})) = (sin (5 \frac{π}{12}))

tan (\frac{5 π}{12}) = tan (\frac{π}{4} + \frac{π}{6})

sin^{2} (θ) = csc^{2} (θ)

tan (x) (sec^{2} (x) - 1) = tan^{3} (x)

Is sec(x)-tan(x)=(cos^2(x))/(sin(x)) ?
The answer to whether sec(x)-tan(x)=(cos^2(x))/(sin(x)) is False