Is (sin(x))/(cos(x)+sin(x))=11 ?

The answer to whether (sin(x))/(cos(x)+sin(x))=11 is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove (sin(x))/(cos(x)+sin(x))=11

prove

\frac{sin ( x )}{cos ( x ) + sin ( x )} = 11

False

Solution steps

\frac{sin ( x )}{cos ( x ) + sin ( x )} = 11

Show that the two sides are not equal

For

\frac{sin ( x )}{cos ( x ) + sin ( x )} = 11

plug in

x = 0

\frac{sin ( 0 )}{cos ( 0 ) + sin ( 0 )} = 0

\frac{sin ( 0 )}{cos ( 0 ) + sin ( 0 )}

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= \frac{0}{1 + 0}

Simplify

= 0

The two sides are not equal

\Rightarrow False

\frac{1 + cos ( a )}{sin ( a )} = cot (\frac{a}{s})

cot (x) (1 - cos (2 x)) = 2 cos^{2} (x) tan (x)

8 \cdot sin^{4} (θ) = cos (4 θ) + 4 \cdot cos (2 θ) - 3

\frac{1 - cos ( 2 u )}{sin ( u )} = 2 sin (u)

tan^{2} (θ) = sin^{2} (θ) sec^{2} (θ)

Is (sin(x))/(cos(x)+sin(x))=11 ?
The answer to whether (sin(x))/(cos(x)+sin(x))=11 is False