Is sec(θ)(cos(θ)+cot(θ))=csc(θ) ?

The answer to whether sec(θ)(cos(θ)+cot(θ))=csc(θ) is False

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prove sec(θ)(cos(θ)+cot(θ))=csc(θ)

prove

sec (θ) (cos (θ) + cot (θ)) = csc (θ)

False

Solution steps

sec (θ) (cos (θ) + cot (θ)) = csc (θ)

Show that the two sides are not equal

For

sec (θ) (cos (θ) + cot (θ)) = csc (θ)

plug in

θ = 1

sec (1) (cos (1) + cot (1)) = 2.18839 \dots

sec (1) (cos (1) + cot (1))

Refine to a decimal form

= 2.18839 \dots

csc (1) = 1.18839 \dots

csc (1)

Refine to a decimal form

= 1.18839 \dots

The two sides are not equal

\Rightarrow False

cos (θ) = \frac{11}{6}

1 - sin^{2} (\frac{x}{4}) = cos (\frac{x}{2})

\frac{csc ( θ ) + sec ( θ )}{csc ( θ )} = csc (θ)

sec (x) + 1 = \frac{cos ( x ) + 1}{cos ( x )}

cos (0) sin (0) = - sin (0)

Is sec(θ)(cos(θ)+cot(θ))=csc(θ) ?
The answer to whether sec(θ)(cos(θ)+cot(θ))=csc(θ) is False