Is (1-cos(x))-cos(y)=sin(x+y) ?

The answer to whether (1-cos(x))-cos(y)=sin(x+y) is False

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prove (1-cos(x))-cos(y)=sin(x+y)

prove

(1 - cos (x)) - cos (y) = sin (x + y)

False

Solution steps

1 - cos (x) - cos (y) = sin (x + y)

Show that the two sides are not equal

For

1 - cos (x) - cos (y) = sin (x + y)

plug in

x = 0

For

1 - cos (x) - cos (y) = sin (x + y)

plug in

y = 1

1 - cos (0) - cos (1) = - 0.54030 \dots

1 - cos (0) - cos (1)

Refine to a decimal form

= - 0.54030 \dots

sin (0 + 1) = 0.84147 \dots

sin (0 + 1)

Refine to a decimal form

= 0.84147 \dots

The two sides are not equal

\Rightarrow False

1 - sin (x) = cos^{2} (x)

csc (θ) \cdot sec (θ) - cot (θ) = tan (θ)

1 + cos (2 x) + 2 sin^{(2)} (x) = 2

3 + 5 sin^{2} (a) = 8 - 5 cos^{2} (a)

(sec^{2} (y) - 1) (sin^{2} (y) - 1) = - sin^{2} (y)

Is (1-cos(x))-cos(y)=sin(x+y) ?
The answer to whether (1-cos(x))-cos(y)=sin(x+y) is False