Is cos^2(x)-cos^2(90-x)=1-2sin(x) ?

The answer to whether cos^2(x)-cos^2(90-x)=1-2sin(x) is False

Popular >

prove cos^2(x)-cos^2(90-x)=1-2sin(x)

prove

cos^{2} (x) - cos^{2} (9 0^{\circ} - x) = 1 - 2 sin (x)

False

Solution steps

cos^{2} (x) - cos^{2} (9 0^{\circ} - x) = 1 - 2 sin (x)

Show that the two sides are not equal

For

cos^{2} (x) - cos^{2} (9 0^{\circ} - x) = 1 - 2 sin (x)

plug in

x = 1

cos^{2} (1) - cos^{2} (9 0^{\circ} - 1) = - 0.41614 \dots

cos^{2} (1) - cos^{2} (9 0^{\circ} - 1)

Refine to a decimal form

= - 0.41614 \dots

1 - 2 sin (1) = - 0.68294 \dots

1 - 2 sin (1)

Refine to a decimal form

= - 0.68294 \dots

The two sides are not equal

\Rightarrow False

sec^{2} (t) csc^{2} (t) = sec^{2} (t) + csc^{2} (t)

\frac{1}{1 + sin ( x )} + \frac{1}{1 + csc ( x )} = 1

sin^{2} (θ) cos^{2} (θ) = 1

sec^{2} (x) cos^{2} (x) + cot^{2} (x) = csc^{2} (x)

\frac{1 - cos ( θ ) - 1 + cos ( θ )}{sin ( θ )} = 0

Is cos^2(x)-cos^2(90-x)=1-2sin(x) ?
The answer to whether cos^2(x)-cos^2(90-x)=1-2sin(x) is False