Is sec(x)tan(x)=-tan(x)sec(x) ?

The answer to whether sec(x)tan(x)=-tan(x)sec(x) is False

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prove sec(x)tan(x)=-tan(x)sec(x)

prove

sec (x) tan (x) = - tan (x) sec (x)

False

Solution steps

sec (x) tan (x) = - tan (x) sec (x)

Show that the two sides are not equal

For

sec (x) tan (x) = - tan (x) sec (x)

plug in

x = 1

sec (1) tan (1) = 2.88247 \dots

sec (1) tan (1)

Refine to a decimal form

= 2.88247 \dots

- tan (1) sec (1) = - 2.88247 \dots

- tan (1) sec (1)

Refine to a decimal form

= - 2.88247 \dots

The two sides are not equal

\Rightarrow False

\frac{1}{csc ( Y ) - cot ( Y )} = csc (Y) + cot (Y)

cos (π + θ) + cos (π - θ) = - 2 cos (θ)

sin (cot (x) + tan (x)) = sec (x)

sin^{2} (2 x) = 4 sin^{2} (x) \cdot cos^{2} (x)

\frac{sec ( x ) csc ( x )}{2} = csc (2 x)

Is sec(x)tan(x)=-tan(x)sec(x) ?
The answer to whether sec(x)tan(x)=-tan(x)sec(x) is False