Is sin(x)cos(x)-2tan(x)=tan(x)cos(2x) ?

The answer to whether sin(x)cos(x)-2tan(x)=tan(x)cos(2x) is False

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prove sin(x)cos(x)-2tan(x)=tan(x)cos(2x)

prove

sin (x) cos (x) - 2 tan (x) = tan (x) cos (2 x)

False

Solution steps

sin (x) cos (x) - 2 tan (x) = tan (x) cos (2 x)

Show that the two sides are not equal

For

sin (x) cos (x) - 2 tan (x) = tan (x) cos (2 x)

plug in

x = 1

sin (1) cos (1) - 2 tan (1) = - 2.66016 \dots

sin (1) cos (1) - 2 tan (1)

Refine to a decimal form

= - 2.66016 \dots

tan (1) cos (2 \cdot 1) = - 0.64811 \dots

tan (1) cos (2 \cdot 1)

Refine to a decimal form

= - 0.64811 \dots

The two sides are not equal

\Rightarrow False

cot^{2} (x) - cos^{2} (x) = cot^{2} (x) cot (x)

sin^{2} (3 2^{\circ}) + cos^{2} (x) = 1

\frac{sin ^{2} ( x )}{1 - sin ^{2} ( x )} = sec^{2} (x) - 1

cos (θ) = - \frac{3}{4}

sin (75) = sin (\frac{150}{2})

Is sin(x)cos(x)-2tan(x)=tan(x)cos(2x) ?
The answer to whether sin(x)cos(x)-2tan(x)=tan(x)cos(2x) is False