Is 1/(cos(θ)sin(θ))=(csc(θ))/(cos(θ)) ?

The answer to whether 1/(cos(θ)sin(θ))=(csc(θ))/(cos(θ)) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 1/(cos(θ)sin(θ))=(csc(θ))/(cos(θ))

prove

\frac{1}{cos ( θ ) sin ( θ )} = \frac{csc ( θ )}{cos ( θ )}

True

Solution steps

\frac{1}{cos ( θ ) sin ( θ )} = \frac{csc ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

\Rightarrow True

sin (2 x) = sin (x) + 1

sin (x) (tan (x)) + cos (x) = sec (x)

sec (β) - cos (β) = tan (β) sin (β)

\frac{sin ( y ^{2} )}{cos ( y )} = sec (y) - cos (y)

sin^{2} (\frac{π}{4} - 2 π) = cos^{2} (\frac{π}{4} - 2 π)

Is 1/(cos(θ)sin(θ))=(csc(θ))/(cos(θ)) ?
The answer to whether 1/(cos(θ)sin(θ))=(csc(θ))/(cos(θ)) is True