Is csc(θ)-cot(θ)=(sin(θ))/(1-cos(θ)) ?

The answer to whether csc(θ)-cot(θ)=(sin(θ))/(1-cos(θ)) is False

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prove csc(θ)-cot(θ)=(sin(θ))/(1-cos(θ))

prove

csc (θ) - cot (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

False

Solution steps

csc (θ) - cot (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

Show that the two sides are not equal

\Rightarrow False

2 csc (2 x) = tan (x) = cot (x)

\frac{1}{cos ( θ )} \cdot sin (θ) = tan (θ)

sin (4 x) - cos (4 x) = cos (x)

cos (2 x) - sin^{2} (x) = cos^{2} (x) + 3 cos (x)

cos^{2} (θ) = \frac{( 1 + cos ( 2 θ ) )}{2}

Is csc(θ)-cot(θ)=(sin(θ))/(1-cos(θ)) ?
The answer to whether csc(θ)-cot(θ)=(sin(θ))/(1-cos(θ)) is False