Is (cos(θ))^2(sec(θ))^2=1 ?

The answer to whether (cos(θ))^2(sec(θ))^2=1 is True

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prove (cos(θ))^2(sec(θ))^2=1

prove

(cos (θ))^{2} (sec (θ))^{2} = 1

True

Solution steps

(cos (θ))^{2} (sec (θ))^{2} = 1

Manipulating left side

(cos (θ))^{2} (sec (θ))^{2}

Simplify

= cos^{2} (θ) sec^{2} (θ)

Express with sin, cos

= 1

We showed that the two sides could take the same form

\Rightarrow True

sin (β) = \frac{1}{4}

3 - 6 sin^{2} (x) = 0

cos (\frac{a}{2}) = \frac{1 + cos ( a )}{2}

sin (β) = \frac{1}{2}

cos^{4} (θ) = \frac{1}{4} + \frac{cos ( 2 θ )}{2} + \frac{cos ^{2} ( 2 θ )}{4}

Is (cos(θ))^2(sec(θ))^2=1 ?
The answer to whether (cos(θ))^2(sec(θ))^2=1 is True