Is (1-cos(θ))(1-cos(θ))= 1/(csc^2(θ)) ?

The answer to whether (1-cos(θ))(1-cos(θ))= 1/(csc^2(θ)) is False

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prove (1-cos(θ))(1-cos(θ))= 1/(csc^2(θ))

prove

(1 - cos (θ)) (1 - cos (θ)) = \frac{1}{csc ^{2} ( θ )}

False

Solution steps

(1 - cos (θ)) (1 - cos (θ)) = \frac{1}{csc ^{2} ( θ )}

Show that the two sides are not equal

\Rightarrow False

cot (- θ) = - cot (θ)

sin^{2} (15 x) + cos^{2} (15 x) = 1

cos (2 x) cos (x) - sin (2 x) sin (x) = 4 cos^{3} (x) - 3 cos (x)

\frac{( cot ( x ) + tan ( x ) )}{csc ( x )} = sec (x)

csc^{2} (b) - csc^{2} (b) cos^{2} (b) = 1

Is (1-cos(θ))(1-cos(θ))= 1/(csc^2(θ)) ?
The answer to whether (1-cos(θ))(1-cos(θ))= 1/(csc^2(θ)) is False