Is tan^{-3}(x)=(tan(x))^{-3} ?

The answer to whether tan^{-3}(x)=(tan(x))^{-3} is True

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prove tan^{-3}(x)=(tan(x))^{-3}

prove

tan^{- 3} (x) = (tan (x))^{- 3}

True

Solution steps

tan^{- 3} (x) = (tan (x))^{- 3}

The two sides are the same

\Rightarrow True

\frac{1}{- 6 csc ^{2} ( 6 x - 1 )} = - \frac{sin ^{2} ( 6 x - 1 )}{6}

sin (x) - tan (x) = \frac{1}{sec ( x ) + tan ( x )}

csc (2 x) = \frac{- 2 3}{3}

\frac{sec ( θ ) - 1}{sec ( θ ) + 1} = \frac{tan ( θ ) - sin ( θ )}{tan ( θ ) + sin ( θ )}

cos^{4} (a) - sin^{4} (a) + 1 = 2 cos^{2} (a)

Is tan^{-3}(x)=(tan(x))^{-3} ?
The answer to whether tan^{-3}(x)=(tan(x))^{-3} is True