Is 4cot(θ)=cot(θ)sin^2(θ) ?

The answer to whether 4cot(θ)=cot(θ)sin^2(θ) is False

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prove 4cot(θ)=cot(θ)sin^2(θ)

prove

4 cot (θ) = cot (θ) sin^{2} (θ)

False

Solution steps

4 cot (θ) = cot (θ) sin^{2} (θ)

Show that the two sides are not equal

For

4 cot (θ) = cot (θ) sin^{2} (θ)

plug in

θ = 1

4 cot (1) = 2.56837 \dots

4 cot (1)

Refine to a decimal form

= 2.56837 \dots

cot (1) sin^{2} (1) = 0.45464 \dots

cot (1) sin^{2} (1)

Refine to a decimal form

= 0.45464 \dots

The two sides are not equal

\Rightarrow False

cos (2 θ) + 1 = 2 cos^{2} (θ)

(3 sin (x) + 3 cos (x))^{2} = 9 + 9 sin (2 x)

- 2 cos (x) sec^{2} (x) = - \frac{2}{cos ( x )}

1 + sin (4 a) + sin (2 a) = sin (2 a)

cot (x) sec (x) = \frac{1}{sin ( x )}

Is 4cot(θ)=cot(θ)sin^2(θ) ?
The answer to whether 4cot(θ)=cot(θ)sin^2(θ) is False