Is 1+tan^2(θ)= 1/(cos(θ)) ?

The answer to whether 1+tan^2(θ)= 1/(cos(θ)) is False

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prove 1+tan^2(θ)= 1/(cos(θ))

prove

1 + tan^{2} (θ) = \frac{1}{cos ( θ )}

False

Solution steps

1 + tan^{2} (θ) = \frac{1}{cos ( θ )}

Show that the two sides are not equal

For

1 + tan^{2} (θ) = \frac{1}{cos ( θ )}

plug in

θ = 1

1 + tan^{2} (1) = 3.42551 \dots

1 + tan^{2} (1)

Refine to a decimal form

= 3.42551 \dots

\frac{1}{cos ( 1 )} = 1.85081 \dots

\frac{1}{cos ( 1 )}

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

cot^{2} (x) = - 1 + csc^{2} (x)

sin (x) + 5 \cdot cos (x) = 1

sin (2 x) - cos (2 x) = tan (2 x) - 1

0 = 0 (2) cos (θ)

(sec (e) - 1) (sec (e) + 1) = tan^{2} (e)

Is 1+tan^2(θ)= 1/(cos(θ)) ?
The answer to whether 1+tan^2(θ)= 1/(cos(θ)) is False