Is 2cot(x)+cos(x)-sec(x)=cot(x) ?

The answer to whether 2cot(x)+cos(x)-sec(x)=cot(x) is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 2cot(x)+cos(x)-sec(x)=cot(x)

prove

2 cot (x) + cos (x) - sec (x) = cot (x)

False

Solution steps

2 cot (x) + cos (x) - sec (x) = cot (x)

Show that the two sides are not equal

For

2 cot (x) + cos (x) - sec (x) = cot (x)

plug in

x = 1

2 cot (1) + cos (1) - sec (1) = - 0.02632 \dots

2 cot (1) + cos (1) - sec (1)

Refine to a decimal form

= - 0.02632 \dots

cot (1) = 0.64209 \dots

cot (1)

Refine to a decimal form

= 0.64209 \dots

The two sides are not equal

\Rightarrow False

(tan (θ) + cot (θ)) sin (θ) cos (θ) = 1

3 (tan (x)) + 12 = 3

2 cos (x) tan (x) cot (x) = 2

sin (θ) = 0.2

\frac{cos ( 4 t ) - cos ( 2 t )}{sin ( 4 t ) + sin ( 2 t )} = - tan (t)

Is 2cot(x)+cos(x)-sec(x)=cot(x) ?
The answer to whether 2cot(x)+cos(x)-sec(x)=cot(x) is False