Is 1=(sec(θ)cot(θ))/(csc(θ))-cot^2(θ) ?

The answer to whether 1=(sec(θ)cot(θ))/(csc(θ))-cot^2(θ) is False

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prove 1=(sec(θ)cot(θ))/(csc(θ))-cot^2(θ)

prove

1 = \frac{sec ( θ ) cot ( θ )}{csc ( θ )} - cot^{2} (θ)

False

Solution steps

1 = \frac{sec ( θ ) cot ( θ )}{csc ( θ )} - cot^{2} (θ)

Show that the two sides are not equal

\Rightarrow False

(sec (α) + csc (α)) (cos (α) - sin (α)) = cot (α) - tan (α)

\frac{tan ^{2} ( θ )}{sec ^{2} ( θ )} = (1)

1 - (- cos (x))^{2} = 1 + cos^{2} (x)

cos (x) = \frac{( csc ( x ) cot ( x ) )}{csc ^{2} ( x )}

csc^{2} (\frac{x}{2}) = \frac{2 sec ( x )}{sec ( x ) - 1}

Is 1=(sec(θ)cot(θ))/(csc(θ))-cot^2(θ) ?
The answer to whether 1=(sec(θ)cot(θ))/(csc(θ))-cot^2(θ) is False