Is (sin^2(x))/1*1/(sin^2(x))=1 ?

The answer to whether (sin^2(x))/1*1/(sin^2(x))=1 is True

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prove (sin^2(x))/1*1/(sin^2(x))=1

prove

\frac{sin ^{2} ( x )}{1} \cdot \frac{1}{sin ^{2} ( x )} = 1

True

Solution steps

\frac{sin ^{2} ( x )}{1} \cdot \frac{1}{sin ^{2} ( x )} = 1

Manipulating left side

\frac{sin ^{2} ( x )}{1} \frac{1}{sin ^{2} ( x )}

Simplify

\frac{1}{sin ^{2} ( x )} \frac{sin ^{2} ( x )}{1} : 1

= 1

We showed that the two sides could take the same form

\Rightarrow True

\frac{1}{2} cot (x) - \frac{1}{2} tan (x) = cot (2 x)

cos^{2} (2 x) - sin^{2} (2 x) = 0

cos (x + \frac{π}{6}) = \frac{3}{2} cos (x) - \frac{1}{2} sin (x)

sin^{2} (x) sin^{2} (x) = sin^{4} (x)

\frac{2 cos ^{2} ( x )}{sin ( 2 x )} = \frac{1}{tan ( x )}

Is (sin^2(x))/1*1/(sin^2(x))=1 ?
The answer to whether (sin^2(x))/1*1/(sin^2(x))=1 is True